4x[5x+1][x+3]=5[x+1][x+2]

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Solution for 4x[5x+1][x+3]=5[x+1][x+2] equation: 


Simplifying
4x[5x + 1][x + 3] = 5[x + 1][x + 2]

Reorder the terms:
4x[1 + 5x][x + 3] = 5[x + 1][x + 2]

Reorder the terms:
4x[1 + 5x][3 + x] = 5[x + 1][x + 2]

Multiply [1 + 5x] * [3 + x]
4x[1[3 + x] + 5x * [3 + x]] = 5[x + 1][x + 2]
4x[[3 * 1 + x * 1] + 5x * [3 + x]] = 5[x + 1][x + 2]
4x[[3 + 1x] + 5x * [3 + x]] = 5[x + 1][x + 2]
4x[3 + 1x + [3 * 5x + x * 5x]] = 5[x + 1][x + 2]
4x[3 + 1x + [15x + 5x2]] = 5[x + 1][x + 2]

Combine like terms: 1x + 15x = 16x
4x[3 + 16x + 5x2] = 5[x + 1][x + 2]
[3 * 4x + 16x * 4x + 5x2 * 4x] = 5[x + 1][x + 2]
[12x + 64x2 + 20x3] = 5[x + 1][x + 2]

Reorder the terms:
12x + 64x2 + 20x3 = 5[1 + x][x + 2]

Reorder the terms:
12x + 64x2 + 20x3 = 5[1 + x][2 + x]

Multiply [1 + x] * [2 + x]
12x + 64x2 + 20x3 = 5[1[2 + x] + x[2 + x]]
12x + 64x2 + 20x3 = 5[[2 * 1 + x * 1] + x[2 + x]]
12x + 64x2 + 20x3 = 5[[2 + 1x] + x[2 + x]]
12x + 64x2 + 20x3 = 5[2 + 1x + [2 * x + x * x]]
12x + 64x2 + 20x3 = 5[2 + 1x + [2x + x2]]

Combine like terms: 1x + 2x = 3x
12x + 64x2 + 20x3 = 5[2 + 3x + x2]
12x + 64x2 + 20x3 = [2 * 5 + 3x * 5 + x2 * 5]
12x + 64x2 + 20x3 = [10 + 15x + 5x2]

Solving
12x + 64x2 + 20x3 = 10 + 15x + 5x2

Solving for variable 'x'.

Reorder the terms:
-10 + 12x + -15x + 64x2 + -5x2 + 20x3 = 10 + 15x + 5x2 + -10 + -15x + -5x2

Combine like terms: 12x + -15x = -3x
-10 + -3x + 64x2 + -5x2 + 20x3 = 10 + 15x + 5x2 + -10 + -15x + -5x2

Combine like terms: 64x2 + -5x2 = 59x2
-10 + -3x + 59x2 + 20x3 = 10 + 15x + 5x2 + -10 + -15x + -5x2

Reorder the terms:
-10 + -3x + 59x2 + 20x3 = 10 + -10 + 15x + -15x + 5x2 + -5x2

Combine like terms: 10 + -10 = 0
-10 + -3x + 59x2 + 20x3 = 0 + 15x + -15x + 5x2 + -5x2
-10 + -3x + 59x2 + 20x3 = 15x + -15x + 5x2 + -5x2

Combine like terms: 15x + -15x = 0
-10 + -3x + 59x2 + 20x3 = 0 + 5x2 + -5x2
-10 + -3x + 59x2 + 20x3 = 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
-10 + -3x + 59x2 + 20x3 = 0

The solution to this equation could not be determined.

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